Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 3 - Introduction to Graphing - 3.4 Rates - 3.4 Exercise Set: 37

Answer

$-10,000$ people per year This means that from the year 2000 to 2010, the population in Cleveland decreased at a rate of 10,000 people per year.

Work Step by Step

In the year 2000, the population in Cleveland was 475,000. In the year 2010, the population in Cleveland was 375,000. The increase (or decrease) in population is: $=375,000-475,000=-100,000$ The time is: $=2010-2000=10$ years Thus, the average rate is: $=\dfrac{-100000\text{ people}}{10 \text{ years}}=-10,000$ people per year
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