Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 3 - Introduction to Graphing - 3.3 Graphing and Intercepts - 3.3 Exercise Set - Page 180: 109

Answer

x-intercept: $(0.02, 0)$ y-intercept: $(0, 0.04)$ Refer to the graph below

Work Step by Step

Find the x-intercept by setting $y=0$ then solving for $x$: $50x+25y=1 \\50x+25(0)=1 \\50x=1 \\\frac{50x}{50}=\frac{1}{50} \\x=0.02$ Thus, the x-intercept is $(0.02, 0)$. Find the y-intercept by setting $x=0$ then solving for $y$: $50x+25y=1 \\50(0)+25y=1 \\25y=1 \\\frac{25y}{25}=\frac{1}{25} \\y=0.04$ Thus, the y-intercept is $(0, 0.04)$. Use a graphing utility to graph the equation and verify the intercepts. (Refer to the attached image below for the graph.)
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