Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 3 - Introduction to Graphing - 3.3 Graphing and Intercepts - 3.3 Exercise Set: 100

Answer

$C=12$

Work Step by Step

The x-intercept of a linear equation can be found by setting $y=0$ then solving for $x$. Set $y=0$ then solve for $x$ to obtain: $3x+C=5y \\3x+C=5(0) \\3x+C=0 \\3x=0-C \\3x=-C \\\frac{3x}{3}=-\frac{C}{3} \\x =-\frac{C}{3}$ The x-intercept is given to be $(-4, 0)$. This means that: $-\frac{C}{3}=-4$ Solve the equation to obtain: $-\frac{C}{3}=-4 \\-3 \cdot (\frac{-C}{3}=-3(-4) \\C=12$
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