Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 3 - Introduction to Graphing - 3.3 Graphing and Intercepts - 3.3 Exercise Set - Page 179: 26

Answer

x-intercept: $(-20, 0)$ y-intercept: $(0, \frac{50}{3})$

Work Step by Step

To find the x-intercept, set $y=0$ then solve for $x$: $-5x+6y=100 \\-5x+6(0)=100 \\-5x=100 \\\frac{-5x}{-5}=\frac{100}{-5} \\x=-20$ Thus, the x-intercept of the graph of the given equation is $(-20, 0)$. To find the y-intercept, set $x=0$ then solve for $y$: $-5x+6y=100 \\-5(0)+6y=100 \\6y=100 \\\frac{6y}{6}=\frac{100}{6} \\y=\frac{50}{3}$ Thus, the y-intercept of the graph of the given equation is $(0, \frac{50}{3})$.
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