Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 2 - Equations, Inequalities, and Problem Solving - 2.4 Applications with Percent - 2.4 Exercise Set: 90

Answer

$-3$

Work Step by Step

$\bf{\text{Solution Outline:}}$ Interchange the numerator and the denominator to get the reciprocal of the given expression, $ -\dfrac{1}{3} .$ $\bf{\text{Solution Details:}}$ Interchanging the numerator and the denominator, the reciprocal of the given expression is \begin{array}{l}\require{cancel} -\dfrac{3}{1} \\\\= -3 .\end{array}
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