Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 2 - Equations, Inequalities, and Problem Solving - 2.3 Formulas - 2.3 Exercise Set - Page 102: 69

Answer

$V=27 \text{ in}^3$

Work Step by Step

The volume of the cube with side $s$ is $V=s^3.$ The surface area $S=6s^2$. We know that surface area is $54 \text{ in}^2$. We determine the side $s$: $$54 \text{ in}^2 = 6s^2$$ $$s^2=9 \text{ in}^2$$ $$s = 3 \text{ in}$$ Now it's easy to find the volume. $$V=(3 \text{ in})^3=27 \text{ in}^3$$
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