## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson

# Chapter 2 - Equations, Inequalities, and Problem Solving - 2.3 Formulas - 2.3 Exercise Set: 33

#### Answer

$T=\dfrac{550H}{V}$

#### Work Step by Step

$\bf{\text{Solution Outline:}}$ To solve the given equation, $H=\dfrac{TV}{550}$ for $T ,$ use the properties of equality to isolate the variable. $\bf{\text{Solution Details:}}$ Using the properties of equality to isolate the variable, the equation above is equivalent to \begin{array}{l}\require{cancel} H=\dfrac{TV}{550} \\\\ 550\cdot H=550\cdot\dfrac{TV}{550} \\\\ 550H=TV \\\\ \dfrac{550H}{V}=\dfrac{TV}{V} \\\\ \dfrac{550H}{V}=T \\\\ T=\dfrac{550H}{V} .\end{array}

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