Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 2 - Equations, Inequalities, and Problem Solving - 2.3 Formulas - 2.3 Exercise Set - Page 100: 19

Answer

$l=\dfrac{P-2w}{2}$

Work Step by Step

$\bf{\text{Solution Outline:}}$ To solve the given equation, $ P=2l+2w $ for $ l ,$ use the properties of equality to isolate the variable. $\bf{\text{Solution Details:}}$ Using the properties of equality to isolate the variable, the equation above is equivalent to \begin{array}{l}\require{cancel} P=2l+2w \\\\ P-2w=2l \\\\ \dfrac{P-2w}{2}=\dfrac{2l}{2} \\\\ \dfrac{P-2w}{2}=l \\\\ l=\dfrac{P-2w}{2} .\end{array}
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