Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 2 - Equations, Inequalities, and Problem Solving - 2.2 Using the Principles Together - 2.2 Exercise Set - Page 94: 44

Answer

$y=4$

Work Step by Step

By combining like terms and by using the properties of equality, the solution to the given equation, $ 5y+3=2y+15 $, is \begin{array}{l}\require{cancel} 5y-2y=15-3 \\\\ 3y=12 \\\\ y=\dfrac{12}{3} \\\\ y=4 .\end{array} Checking: \begin{array}{l}\require{cancel} 5(4)+3=2(4)+15 \\\\ 20+3=8+15 \\\\ 23=23 \text{ (TRUE)} .\end{array} Hence, $ y=4 $.
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