Answer
$\frac{n!}{(n-r)!(n-(n-r))!}=\frac{n!}{(n-r)!r!}$
Work Step by Step
The binomial coefficient of
$\binom{n}{r}=\frac{n!}{r!(n-r)!}$
Which equals to
$\binom{n}{n-r}=\frac{n!}{(n-r)!(n-(n-r))!}=\frac{n!}{(n-r)!r!}$
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