Chapter 14 - Sequences, Series, and the Binomial Theorem - 14.2 Arithmetic Sequences and Series - 14.2 Exercise Set - Page 902: 18

$a_{10}=\$7941.62$

We have to find the $10$th term of the arithmetic sequence: $2345.78, 2967.54, 3589.30,\cdots$ Any term of the arithmetic sequence can be found as $a_n=a_1+d(n-1).$ In our case $a_1=2345.78,$ $d=a_2-a_1=2967.54-2345.78=621.76$ $n=10.$ Hence $a_{10}=2345.78+621.76(10-1)=7941.62$