Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 14 - Sequences, Series, and the Binomial Theorem - 14.1 Sequences and Series - 14.1 Exercise Set: 40

Answer

$a_n=(-1)^{n}n$

Work Step by Step

If we look at the pattern: $ -1, 2, -3, 4, ...$ $(-1)^1(1), (-1)^2(2), (-1)^3(3), (-1)^4(4), ...$ Hence, the nth term in the sequence is: $a_n=(-1)^{n}n$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.