Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 14 - Sequences, Series, and the Binomial Theorem - 14.1 Sequences and Series - 14.1 Exercise Set: 20

Answer

9680

Work Step by Step

If we want to find the 22nd term, we have to substitute $n$ by 22: $a_{22}=4(22)^2(2(22)-39)=4\times484\times(44-39)=9680$
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