Answer
$x={{y}^{2}}-4y+2$
Work Step by Step
$x={{y}^{2}}-4y+2$ (equation - 1)
$\begin{align}
& y=-\frac{b}{2a} \\
& =-\frac{\left( -4 \right)}{2\cdot \left( 1 \right)} \\
& =2
\end{align}$
Now for the x value put $y=2$ in equation (1).
$\begin{align}
& x={{\left( 2 \right)}^{2}}-4\cdot 2+2 \\
& =4-8+2 \\
& =-2
\end{align}$
The vertex is$\left( -2,2 \right)$.
Now choose some value of x on both sides of the vertex and compute the corresponding y value.
$\begin{matrix}
x & y \\
7 & -1 \\
2 & 0 \\
-1 & 1 \\
-2 & 2 \\
-1 & 3 \\
\end{matrix}$
