Answer
$\dfrac{1}{2}$
Work Step by Step
Using the properties of logarithms, the given expression, $
\log_b \sqrt{b}
,$ is equivalent to
\begin{array}{l}\require{cancel}
\log_b b^{1/2}
\\\\=
\dfrac{1}{2}\log_b b
.\end{array}
Since $\log_b b=1,$ the expression above, $
\dfrac{1}{2}\log_b b
$, evaluates to
\begin{array}{l}\require{cancel}
\dfrac{1}{2}(1)
\\\\=
\dfrac{1}{2}
.\end{array}
