## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson

# Chapter 11 - Quadratic Functions and Equations - 11.1 Quadratic Equations - 11.1 Exercise Set: 7

#### Answer

$x=\pm10$

#### Work Step by Step

Since $x^2=a$ implies $x=\pm\sqrt{a}$ (the Square Root Principle), then the solutions to the given equation, $x^2=100 ,$ are \begin{array}{l}\require{cancel} x=\pm\sqrt{100} \\\\ x=\pm\sqrt{(10)^2} \\\\ x=\pm10 .\end{array}

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