Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - Test: Chapter 10 - Page 695: 17

Answer

$14-19\sqrt{x}-3x$

Work Step by Step

Using the FOIL Method which is given by $(a+b)(c+d)=ac+ad+bc+bd,$ the given expression is equivalent to\begin{array}{l}\require{cancel} (7+\sqrt{x})(2-3\sqrt{x}) \\\\= 7(2)+7(-3\sqrt{x})+\sqrt{x}(2)+\sqrt{x}(-3\sqrt{x}) \\\\= 14-21\sqrt{x}+2\sqrt{x}-3(\sqrt{x})^2 \\\\= 14-21\sqrt{x}+2\sqrt{x}-3x \\\\= 14-19\sqrt{x}-3x .\end{array}
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