Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - Test: Chapter 10 - Page 695: 11

Answer

$\dfrac{10a^2}{3b^3}$

Work Step by Step

Extracting the factors that are perfect powers of the index, the given expression simplifies to \begin{array}{l}\require{cancel} \sqrt{\dfrac{100a^4}{9b^6}} \\\\= \sqrt{\left( \dfrac{10a^2}{3b^3}\right)^2} \\\\= \dfrac{10a^2}{3b^3} .\end{array} Note that all variables are assumed to represent positive numbers.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.