Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - Study Summary - Practice Exercises - Page 690: 2

Answer

$-1$

Work Step by Step

Extracting the factor that is a perfect power of the index, then \begin{array}{l}\require{cancel} \sqrt[3]{-1} \\\\= \sqrt[3]{(-1)^3} \\\\= -1 .\end{array}
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