Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - Mid-Chapter Review - Mixed Review - Page 663: 4

Answer

$-\dfrac{3}{10}$

Work Step by Step

Using concepts of exponents and radicals, the given expression, $ -\sqrt{\dfrac{9}{100}} ,$ is equivalent to \begin{array}{l}\require{cancel} -\sqrt{\dfrac{9}{100}} \\\\= -\sqrt{\left( \dfrac{3}{10} \right)^2} \\\\= -\dfrac{3}{10} .\end{array}
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