Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - 10.7 The Distance Formula, the Midpoint Formula, and Other Applications - 10.7 Exercise Set - Page 679: 73

Answer

$$\left(-\frac{1}{12},\:\frac{1}{24}\right)$$

Work Step by Step

Using the midpoint formula, we find: $$ \left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right) \\ \left(\frac{-\frac{1}{3}+\frac{1}{6}}{2},\:\frac{\frac{5}{6}-\frac{3}{4}}{2}\right)\\ \left(-\frac{1}{12},\:\frac{1}{24}\right)$$
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