Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - 10.6 Solving Radical Equations - 10.6 Exercise Set: 17

Answer

$y=5$

Work Step by Step

Raising both sides to the $\text{ 3rd }$ power, the solution to the given equation, $ \sqrt[3]{y+3}=2 $, is \begin{array}{l} y+3=8 \\\\ y=8-3 \\\\ y=5 .\end{array}
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