Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - 10.6 Solving Radical Equations - 10.6 Exercise Set - Page 668: 11

Answer

$x=\dfrac{16}{3}$

Work Step by Step

Using properties of equality, the given equation, $ \sqrt{3x}+1=5 $, is equivalent to \begin{array}{l} \sqrt{3x}=5-1 \\\\ \sqrt{3x}=4 .\end{array} Raising both sides to the $\text{ 2nd }$ power, the solution to the equation above, $ \sqrt{3x}=4 $, is \begin{array}{l} 3x=16 \\\\ x=\dfrac{16}{3} .\end{array} Upon checking, $ x=\dfrac{16}{3} $ satisfies the given equation.
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