Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - 10.4 Dividing Radical Expressions - 10.4 Exercise Set: 45

Answer

$\dfrac{2\sqrt{15}}{21}$

Work Step by Step

Rationalizing the denominator of the given expression, $ \dfrac{2\sqrt{5}}{7\sqrt{3}} ,$ we find: \begin{array}{l}\require{cancel} \dfrac{2\sqrt{5}}{7\sqrt{3}}\cdot\dfrac{\sqrt{3}}{\sqrt{3}} \\\\= \dfrac{2\sqrt{15}}{7\sqrt{(3)^2}} \\\\= \dfrac{2\sqrt{15}}{7\cdot3} \\\\= \dfrac{2\sqrt{15}}{21} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.