Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - 10.3 Multiplying Radical Expressions - 10.3 Exercise Set - Page 647: 42

Answer

$f(x)=3x\sqrt[3]{x^2}$

Work Step by Step

Using the properties of radicals, the given equation, $ f(x)=\sqrt[3]{27x^5} ,$ simplifies to \begin{array}{l}\require{cancel} f(x)=\sqrt[3]{27x^3\cdot x^2} \\\\ f(x)=\sqrt[3]{(3x)^3\cdot x^2} \\\\ f(x)=3x\sqrt[3]{x^2} \end{array}
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