Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - 10.1 Radical Expressions and Functions - 10.1 Exercise Set: 61

Answer

$\dfrac{2}{3}$

Work Step by Step

Using the properties of radicals, the given expression, $ -\sqrt[5]{-\dfrac{32}{243}} ,$ simplifies to \begin{array}{l} -\sqrt[5]{\left( -\dfrac{2}{3} \right)^5} \\\\= -\left( -\dfrac{2}{3} \right) \\\\= \dfrac{2}{3} .\end{array}
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