Answer
$f(0)=1
,\\\\
f(-1)=\sqrt{2}
,\\\\
f(-10)=\sqrt{101}$
Work Step by Step
$\bf{\text{Solution Outline:}}$
Substitute the given function value in $
f(t)=\sqrt{t^2+1}
.$
$\bf{\text{Solution Details:}}$
If $
t=0
,$ then
\begin{array}{l}\require{cancel}
f(t)=\sqrt{t^2+1}
\\\\
f(0)=\sqrt{0^2+1}
\\\\
f(0)=\sqrt{1}
\\\\
f(0)=1
.\end{array}
If $
t=-1
,$ then
\begin{array}{l}\require{cancel}
f(t)=\sqrt{t^2+1}
\\\\
f(-1)=\sqrt{(-1)^2+1}
\\\\
f(-1)=\sqrt{2}
.\end{array}
If $
t=-10
,$ then
\begin{array}{l}\require{cancel}
f(t)=\sqrt{t^2+1}
\\\\
f(-10)=\sqrt{(-10)^2+1}
\\\\
f(-10)=\sqrt{101}
.\end{array}
Hence,
\begin{array}{l}\require{cancel}
f(0)=1
,\\\\
f(-1)=\sqrt{2}
,\\\\
f(-10)=\sqrt{101}
.\end{array}
