Answer
$f(3)=\sqrt{5}
,\\\\
f(2)=0
,\\\\
f(1)=\text{does not exist}
,\\\\
f(-1)=\text{does not exist}$
Work Step by Step
$\bf{\text{Solution Outline:}}$
Substitute the given function value in $
f(t)=\sqrt{5t-10}
.$
$\bf{\text{Solution Details:}}$
If $
t=3
,$ then
\begin{array}{l}\require{cancel}
f(t)=\sqrt{5t-10}
\\\\
f(3)=\sqrt{5(3)-10}
\\\\
f(3)=\sqrt{5}
.\end{array}
If $
t=2
,$ then
\begin{array}{l}\require{cancel}
f(t)=\sqrt{5t-10}
\\\\
f(2)=\sqrt{5(2)-10}
\\\\
f(2)=0
.\end{array}
If $
t=1
,$ then
\begin{array}{l}\require{cancel}
f(t)=\sqrt{5t-10}
\\\\
f(1)=\sqrt{5(1)-10}
\\\\
f(1)=\sqrt{-5}
\text{ (not a real number)}
.\end{array}
If $
t=-1
,$ then
\begin{array}{l}\require{cancel}
f(t)=\sqrt{5t-10}
\\\\
f(-1)=\sqrt{5(-1)-10}
\\\\
f(1)=\sqrt{-15}
\text{ (not a real number)}
.\end{array}
Hence,
\begin{array}{l}\require{cancel}
f(3)=\sqrt{5}
,\\\\
f(2)=0
,\\\\
f(1)=\text{does not exist}
,\\\\
f(-1)=\text{does not exist}
.\end{array}
