Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1 - Introduction to Algebraic Expressions - Review Exercises: Chapter 1 - Page 77: 72

Answer

a) The rational number named by $0.27272727\cdots$ is $\dfrac{3}{11}$. b) The rational number named by $0.90909090\cdots$ is $\dfrac{10}{11}$.

Work Step by Step

a) We have given $0.18181818\cdots=\dfrac{2}{11}$ and $0.09090909\cdots=\dfrac{1}{11}$. Adding the two equations will give $0.27272727\cdots=\dfrac{2}{11}+\dfrac{1}{11}=\dfrac{3}{11}$ b) We have given $0.09090909\cdots=\dfrac{1}{11}$. Multiply the equation by $10$. We get, $0.90909090\cdots=\dfrac{10}{11}$
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