Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1 - Introduction to Algebraic Expressions - Review Exercises: Chapter 1: 71

Answer

$25,281$

Work Step by Step

Substituting $a=1$ and $b=2$ in the given expression, $ a^{50}-20a^{25}b^4+100b^8 ,$ results to \begin{array}{l}\require{cancel} a^{50}-20a^{25}b^4+100b^8 \\\\= (1)^{50}-20(1)^{25}(2)^4+100(2)^8 \\\\= (1)-20(1)(16)+100(256) \\\\= 1-320+25600 \\\\= 25,281 .\end{array}
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