Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1 - Introduction to Algebraic Expressions - Review Exercises: Chapter 1: 53

Answer

$\dfrac{21}{8}$

Work Step by Step

The given expression, $ (120-6^2)\div(4\cdot8) $, simplifies to \begin{array}{l}\require{cancel} (120-36)\div32 \\\\= 84\div32 \\\\= \dfrac{84}{32} \\\\= \dfrac{\cancel{4}\cdot21}{\cancel{4}\cdot8} \\\\= \dfrac{21}{8} .\end{array}
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