Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1 - Introduction to Algebraic Expressions - Review Exercises: Chapter 1 - Page 76: 46

Answer

$-\dfrac{2}{7}$

Work Step by Step

The given expression, $ \dfrac{2}{3}\cdot\left( -\dfrac{3}{7} \right) $, simplifies to \begin{array}{l}\require{cancel} \dfrac{2(-3)}{3(7)} \\\\= \dfrac{2(-\cancel{3})}{\cancel{3}(7)} \\\\= \dfrac{-2}{7} \\\\= -\dfrac{2}{7} .\end{array}
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