Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1 - Introduction to Algebraic Expressions - Mid-Chapter Review - Mixed Review - Page 37: 17

Answer

$\frac{13}{24}$

Work Step by Step

First, we want to find a common denominator. This needs to be a multiple of both 12 and 8. The smallest number that satisfies this is 24. Rewriting the fractions so that the denominators are both 24, the expression we are trying to evaluate becomes $\frac{11*2}{12*2}-\frac{3*3}{8*3}$. Simplifying: $\frac{11*2}{12*2}-\frac{3*3}{8*3}$ =$\frac{22}{24}-\frac{9}{24}$ =$\frac{22-9}{24}$ =$\frac{13}{24}$.
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