Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1 - Introduction to Algebraic Expressions - 1.8 Exponential Notation and Order of Operations - 1.8 Exercise Set: 78

Answer

$\dfrac{5}{4}$

Work Step by Step

Substituting $ t $ with $ -6 $ in the given expression, $ -30\div t(t+4)^2 $, then, \begin{array}{l}\require{cancel} -30\div (-6)(-6+4)^2 \\\\= -30\div (-6)(-2)^2 \\\\= -30\div (-6)(4) \\\\= -30\div (-24) \\\\= \dfrac{\cancel{-6}\cdot5}{\cancel{-6}\cdot4} \\\\= \dfrac{5}{4} .\end{array}
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