Answer
$17$
Work Step by Step
Substituting $
x
$ with $
3
$, then the given expression, $
\dfrac{x^2+2^x}{x^2-2^x}
$, evaluates to
\begin{array}{l}\require{cancel}
\dfrac{3^2+2^3}{3^2-2^3}
\\\\=
\dfrac{9+8}{9-8}
\\\\=
\dfrac{17}{1}
\\\\=
17
.\end{array}
