Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1 - Introduction to Algebraic Expressions - 1.7 Multiplication and Division of Real Numbers - 1.7 Exercise Set: 105

Answer

$1$

Work Step by Step

The given expression, $ \left( \dfrac{-9}{5} \right)\left( \dfrac{5}{-9} \right) $, simplifies to \begin{array}{l} \dfrac{-9(5)}{5(-9)} \\\\= \dfrac{-45}{-45} \\\\= 1 .\end{array}
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