Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1 - Introduction to Algebraic Expressions - 1.1 Introduction to Algebra - 1.1 Exercise Set - Page 11: 85

Answer

6

Work Step by Step

Evaluate $\frac{a+b}{4}$ where a is twice b and a is 16. Given the value of a, solve for b. $a=2b\longrightarrow$ Substitute the value for a. $16=2b\longrightarrow$ Divide both sides by 2. $16\div2=2b\div2\longrightarrow$ Solve. $8=b$ Substitute for a and b in the original equation and solve. $\frac{a+b}{4}=\frac{16+8}{4}=\frac{24}{4}=6$
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