Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1-4 - Cumulative Review - Page 301: 42

Answer

$$15x^{12}$$

Work Step by Step

We know the following rules of exponents. $$ (1) \ a^m\cdot a^n = a^{m+n} \\ (2) \ (ab)^m =a^mb^m \\ (3) \ (a^m)^n =a^{mn} \\ (4) \ a^{-m} = \frac{1}{a^m} \\ (5)\ \frac{a^m}{a^n} =a^{m-n} \\ (6) \ a^0=1 \\ (7) \ (\frac{a}{b})^m =\frac{a^m}{b^m}$$ Thus, we find: $$-2x^5\left(x^7\right)+\left(x^3\right)^4-\left(4x^5\right)^2\left(-x^2\right)\\ -2x^{12}+x^{12}+4^2x^{12}\\ -x^{12}+4^2x^{12}\\ 15x^{12}$$
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