Answer
$x \lt 16$
Work Step by Step
Add $2x$ to both sides of the inequality:
$x-28+2x\lt 20-2x+2x
\\3x-28\lt 20$
Add $28$ to both sides of the inequality:
$3x-28+28\lt 20+28
\\3x \lt 48$
Divide $3$ to both sides of the inequality:
$\frac{3x}{3} \lt \frac{48}{3}
\\x \lt 16$
