College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.8 - Solving Basic Equations - P.8 Exercises: 12

Answer

(a) yes (b) no

Work Step by Step

(a) Using $x=4$, we get: Left side: $\displaystyle \frac{4^{3/2}}{4-6}=\frac{2^{3}}{-2}=\frac{8}{-2}=-4$ Right side: $(4)-8=-4$ The sides match, so $x=4$ is a solution. (b) Using $x=8$, we get: Left side: $\displaystyle \frac{8^{3/2}}{8-6}=\frac{(2^{3})^{3/2}}{2}=\frac{2^{9/2}}{2}=2^{7/2}$ Right side: $(8)-8=0$ The sides do not match, so $x=8$ is not a solution.
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