College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.7 - Rational Expressions - P.7 Exercises: 84

Answer

$\frac{7-\frac{3}{2}x}{(7-3x)^{3/2}}$

Work Step by Step

We factor out $(7-3x)^{-1/2}$, remembering that $(7-3x)^{-1/2}*(7-3x)=(7-3x)^{1/2}$: $\displaystyle \frac{(7-3x)^{1/2}+\frac{3}{2}x(7-3x)^{-1/2}}{7-3x}=\frac{(7-3x)^{-1/2}(7-3x+\frac{3}{2}x)}{7-3x}=\frac{7-\frac{3}{2}x}{(7-3x)^{3/2}}$
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