College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.3 - Integer Exponents and Scientific Notation - P.3 Exercises: 16

Answer

a. $3^{8}.3^{5} = 3^{13} = 1594323$ b. $6^{0}.6 = 6$ c. $(5^{4})^{2} = 5^{8} = 390625$

Work Step by Step

a. $3^{8}.3^{5} = 3^{8+5} = 3^{13} = 3\times3\times3\times3\times3\times3\times3\times3\times3\times3\times3\times3\times3 = 1594323$ b. $6^{0}.6 = 1\times6= 6$ c. $(5^{4})^{2} = 5^{4\times2} = 5^{8} = 5\times5\times5\times5\times5\times5\times5\times5 = 390625$
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