College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.3 - Integer Exponents and Scientific Notation - P.3 Exercises - Page 23: 15

Answer

a. $5^{3}.5 = 625$ b. $3^{2}.3^{0} = 9$ c. $(2^{2})^{3} = 64$

Work Step by Step

a. $5^{3}.5 = 5^{3+1} = 5^{4} = 5\times5\times5\times5 = 625$ b. $3^{2}.3^{0} = 3^{2+0} = 3^{2} = 3\times3 = 9$ c. $(2^{2})^{3} = 2^{2\times3} = 2^{6} = 2\times2\times2\times2\times2\times2 = 64$
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