Answer
a.
$-2^{-3}.(-2)^{0} = -\frac{1}{8} $
b.
$-2^{3}.(-2)^{0} = -8 $
c.
$(\frac{-2}{3})^{-3} = -\frac{27}{8}$
Work Step by Step
a.
$-2^{-3}.(-2)^{0} = -\frac{1}{2^{3}} \times 1 = -\frac{1}{2\times2\times2} = -\frac{1}{8} $
b.
$-2^{3}.(-2)^{0} = -(2\times2\times2)\times1 = -8 $
c.
$(\frac{-2}{3})^{-3} = \frac{1}{(\frac{-2}{3})^{3}} = (\frac{-3}{2})^{3} = (-\frac{3}{2})\times(-\frac{3}{2})\times(-\frac{3}{2}) = -\frac{27}{8}$
