College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.2 - Real Numbers - P.2 Exercises: 32

Answer

(a) $\frac{8}{3}$ (b) 3

Work Step by Step

(a) $\frac{2}{\frac{2}{3}}-\frac{\frac{2}{3}}{2}=2\cdot\frac{3}{2}-\frac{2}{3}\cdot\frac{1}{2}=3-\frac{1}{3}=\frac{9}{3}-\frac{1}{3}=\frac{8}{3}$ (b) $\frac{\frac{2}{5}+\frac{1}{2}}{\frac{1}{10}+\frac{3}{15}}=\frac{\frac{2}{5}+\frac{1}{2}}{\frac{1}{10}+\frac{1}{5}}=\frac{\frac{2}{5}+\frac{1}{2}}{\frac{1}{10}+\frac{1}{5}}$ * $ \frac{10}{10}=\frac{\frac{2*10}{5}+\frac{1*10}{2}}{\frac{1*10}{10}+\frac{1*10}{5}}=\frac{4+5}{1+2}=\frac{9}{3}=3$
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