College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 9, Counting and Probability - Section 9.1 - Counting - 9.1 Exercises - Page 658: 60

Answer

4128840588600

Work Step by Step

We first choose 8 to go in the first van. $$C(30,8)$$. Then we choose 11 for the 2nd. $$C(22,11)$$. The rest go in the last van. $$C(22,11)*C(30,8) = \frac{22!*30!}{11!*11!*8!*22!}= 4128840588600$$
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