Answer
Yes, the statement is true.
Work Step by Step
$\displaystyle \left(\begin{array}{l}n\\0\end{array}\right)=\frac{n!}{0!\ n!}=\frac{n!}{1*n!}=1$
$\displaystyle \left(\begin{array}{l}n\\n
\end{array}\right)=\frac{n!}{n!\ 0!}=\frac{n!}{n!*1}=1$
