Answer
The ratios are different so the given sequence is not geometric.
Work Step by Step
A geometric sequence has a common ratio $r$. The common ratio is multiplied to the current term to get the next term of the sequence.
The common ratio is equal to the the quotient of a term and the term before it.
Solve for the ratio of each pair of consecutive terms to obtain:
$\dfrac{48}{3} = 16
\\\dfrac{93}{48}=\dfrac{31}{16}
\\\dfrac{138}{93} = \dfrac{46}{31}$
Since the ratio is common to all pairs f consecutive terms, then the sequence is geometric.
The ratios are different so the given sequence is not geometric.
