Answer
$\$403,500$
Work Step by Step
We know the salary forms an arithmetic sequences with:
$a_1=30000$
And:
$d=2300$
We find the sum after 10 years:
$S_{n}= \frac{n}{2}[2a_1+(n-1)d]=403500$
$S_{10}= \frac{10}{2}[2(30000)+(10-1)(2300)]=403500$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter 8, Sequences and Series - Section 8.2 - Arithmetic Sequences - 8.2 Exercises - Page 608: 73
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