College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 8, Sequences and Series - Section 8.1 - Sequences and Summation Notation - 8.1 Exercises: 6

Answer

$a_1=0$ $a_2=3$ $a_3=8$ $a_4=15$ $a_{100}=9999$

Work Step by Step

We are given: $a_{n}=n^{2}-1$ We evaluate: $a_1=(1)^{2}-1=1-1=0$ $a_2=(2)^{2}-1=4-1=3$ $a_3=(3)^{2}-1=9-1=8$ $a_4=(4)^{2}-1=16-1=15$ $a_{100}=(100)^{2}-1=9999$
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